Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Transformations
Problem 54d
Textbook Question
Describe how each graph is obtained from the graph of 𝔂 = ƒ(x).
d. 𝔂 = ƒ(2x + 1)

1
Start with the graph of the original function \( y = f(x) \). This is your base graph.
To understand the transformation \( y = f(2x + 1) \), first consider the expression inside the function, \( 2x + 1 \). This involves two transformations: a horizontal scaling and a horizontal shift.
The term \( 2x \) indicates a horizontal compression. Since the coefficient of \( x \) is 2, the graph will be compressed horizontally by a factor of \( \frac{1}{2} \). This means that every point on the graph of \( y = f(x) \) will be moved closer to the y-axis by this factor.
Next, consider the \( +1 \) inside the function. This represents a horizontal shift. Specifically, it shifts the graph to the left by 1 unit. This is because the transformation \( x \rightarrow x + 1 \) moves the graph in the opposite direction of the sign.
Combine these transformations: First, compress the graph horizontally by a factor of \( \frac{1}{2} \), and then shift it 1 unit to the left. This will give you the graph of \( y = f(2x + 1) \).
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