Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
4. Applications of Derivatives
Motion Analysis
Problem 23e
Textbook Question
Suppose a stone is thrown vertically upward from the edge of a cliff on Earth with an initial velocity of 32 ft/s from a height of 48 ft above the ground. The height (in feet) of the stone above the ground t seconds after it is thrown is s(t) = -16t2 + 32t + 48.
With what velocity does the stone strike the ground?
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1
Step 1: Understand the problem. We need to find the velocity of the stone when it strikes the ground. The height function is given by s(t) = -16t^2 + 32t + 48, where s(t) is the height in feet and t is the time in seconds.
Step 2: Determine when the stone hits the ground. This occurs when s(t) = 0. Solve the equation -16t^2 + 32t + 48 = 0 to find the time t when the stone reaches the ground.
Step 3: Use the quadratic formula to solve for t. The quadratic formula is t = (-b ± √(b^2 - 4ac)) / (2a), where a = -16, b = 32, and c = 48.
Step 4: Once you have the value of t when the stone hits the ground, find the velocity at that time. The velocity function v(t) is the derivative of the height function s(t).
Step 5: Differentiate s(t) to find v(t). The derivative of s(t) = -16t^2 + 32t + 48 is v(t) = ds/dt = -32t + 32. Substitute the value of t from Step 3 into v(t) to find the velocity when the stone strikes the ground.
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