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Ch. 3 - Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 3, Problem 3.7.47

Theory and Examples


Intersecting normal line The line that is normal to the curve x² + 2xy – 3y² = 0 at (1,1) intersects the curve at what other point?

Verified step by step guidance
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First, find the derivative of the given implicit function \(x^2 + 2xy - 3y^2 = 0\) with respect to \(x\) using implicit differentiation. This will help us find the slope of the tangent line at any point \((x, y)\) on the curve.
Differentiate each term: \(\frac{d}{dx}(x^2) = 2x\), \(\frac{d}{dx}(2xy) = 2y + 2x\frac{dy}{dx}\), and \(\frac{d}{dx}(-3y^2) = -6y\frac{dy}{dx}\). Set the derivative equal to zero: \(2x + 2y + 2x\frac{dy}{dx} - 6y\frac{dy}{dx} = 0\).
Solve for \(\frac{dy}{dx}\) to find the slope of the tangent line: \(\frac{dy}{dx} = \frac{2x + 2y}{6y - 2x}\). Evaluate this derivative at the point \((1, 1)\) to find the slope of the tangent line at that point.
The slope of the normal line is the negative reciprocal of the tangent slope. Calculate this slope and use the point-slope form of a line equation \(y - y_1 = m(x - x_1)\) to find the equation of the normal line at \((1, 1)\).
Substitute the equation of the normal line into the original curve equation \(x^2 + 2xy - 3y^2 = 0\) to find the other point of intersection. Solve the resulting system of equations to find the coordinates of the other intersection point.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Normal Line to a Curve

A normal line to a curve at a given point is perpendicular to the tangent line at that point. To find the equation of the normal line, first determine the slope of the tangent line using derivatives, then use the negative reciprocal of this slope for the normal line. This concept is crucial for understanding how the normal line interacts with the curve.
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Implicit Differentiation

Implicit differentiation is used when dealing with equations where y is not isolated. It involves differentiating both sides of the equation with respect to x, treating y as a function of x. This technique is essential for finding the derivative of the given curve x² + 2xy – 3y² = 0, which helps in determining the slope of the tangent line at a specific point.
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Finding The Implicit Derivative

Intersection of Curves

Finding the intersection of curves involves solving the equations of the curves simultaneously. After determining the equation of the normal line, substitute it back into the original curve equation to find other points of intersection. This concept is key to identifying where the normal line intersects the curve again, beyond the initial point of tangency.
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