Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
1. Limits and Continuity
Introduction to Limits
4:09 minutes
Problem 86
Textbook Question
Textbook QuestionUse an appropriate limit definition to prove the following limits.
lim x→1 (5x−2) =3;
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Limit Definition
The limit definition in calculus refers to the formal approach to determining the value that a function approaches as the input approaches a certain point. Specifically, for a function f(x), the limit as x approaches a value 'a' is L if, for every ε > 0, there exists a δ > 0 such that whenever 0 < |x - a| < δ, it follows that |f(x) - L| < ε. This definition is foundational for proving limits rigorously.
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Direct Substitution
Direct substitution is a method used to evaluate limits by substituting the value that x approaches directly into the function. If the function is continuous at that point, the limit can be found simply by replacing x with the target value. In the case of the limit lim x→1 (5x−2), substituting x = 1 yields the result 3, confirming the limit without further manipulation.
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Continuity of Functions
A function is continuous at a point if the limit of the function as it approaches that point equals the function's value at that point. For the limit lim x→1 (5x−2), the function is a polynomial, which is continuous everywhere. This property allows us to confidently use direct substitution to evaluate the limit, reinforcing the relationship between limits and continuity in calculus.
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