Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Motion Analysis
Problem 3.1.49
Textbook Question
Interpreting the derivative Find the derivative of each function at the given point and interpret the physical meaning of this quantity. Include units in your answer.
An object dropped from rest falls d(t)=16t² feet in t seconds. Find d′(4).

1
First, identify the function given: \( d(t) = 16t^2 \). This represents the distance fallen by an object in feet as a function of time \( t \) in seconds.
To find the derivative \( d'(t) \), apply the power rule of differentiation. The power rule states that if \( f(t) = at^n \), then \( f'(t) = nat^{n-1} \).
Using the power rule, differentiate \( d(t) = 16t^2 \) to get \( d'(t) = 32t \). This derivative represents the velocity of the object in feet per second.
Evaluate the derivative at the given point \( t = 4 \) seconds: \( d'(4) = 32 \times 4 \). This calculation will give the velocity of the object at 4 seconds.
Interpret the result: The value of \( d'(4) \) represents the instantaneous velocity of the object at \( t = 4 \) seconds. The units of this derivative are feet per second, indicating how fast the object is falling at that specific moment in time.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivative
The derivative of a function measures the rate at which the function's value changes as its input changes. In the context of motion, it represents the object's velocity at a specific time. For the function d(t) = 16t², the derivative d′(t) gives the instantaneous velocity of the object at time t.
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Physical Interpretation of Derivatives
In physics, the derivative can be interpreted as a measure of how a physical quantity changes over time. For example, in the case of an object in free fall, the derivative of the distance function with respect to time gives the velocity, which indicates how fast the object is falling at any given moment.
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Units of Measurement
When calculating derivatives in a physical context, it is essential to include units to convey meaningful information. In this case, the distance function d(t) is measured in feet, and time t is measured in seconds. Therefore, the derivative d′(t) will have units of feet per second, representing the velocity of the falling object.
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