Use the second derivative test to find the local extrema of the given function.
$g(x)=x^3-6x^2+9x+2$

Local max of $6$ at $x=1$ , local min of 2 at $x=3$

Local min of $6$ at $x=1$ , local max of 2 at $x=3$

Local max of $6$ at $x=-1$ and $x=1$ , local min of $-6$ at $x=-3$ and $x=3$

No local extrema

Master The Second Derivative Test: Finding Local Extrema with a bite sized video explanation from Callie

Related Videos

Related Practice

Use the second derivative test to find the local extrema of the given function.﻿g(x)=x3−6x2+9x+2g(x)=x^3-6x^2+9x+2g(x)=x3−6x2+9x+2﻿