Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 3.4.17
Textbook Question
Find the slope of the line tangent to the graph of f(x) = x / x+6 at the point (3, 1/3) and at (-2, -1/2).
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1
Step 1: To find the slope of the tangent line to the graph of a function at a given point, we need to find the derivative of the function, f(x). The function given is f(x) = \frac{x}{x+6}.
Step 2: Use the quotient rule to differentiate f(x). The quotient rule states that if you have a function h(x) = \frac{u(x)}{v(x)}, then h'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2}. Here, u(x) = x and v(x) = x + 6.
Step 3: Calculate the derivatives u'(x) and v'(x). For u(x) = x, u'(x) = 1. For v(x) = x + 6, v'(x) = 1.
Step 4: Substitute u(x), v(x), u'(x), and v'(x) into the quotient rule formula to find f'(x). This will give you the expression for the derivative of f(x).
Step 5: Evaluate f'(x) at the given points (3, 1/3) and (-2, -1/2) to find the slopes of the tangent lines at these points. Substitute x = 3 and x = -2 into the expression for f'(x) to find the respective slopes.
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