- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
5. Graphical Applications of Derivatives
Curve Sketching
Problem 4.4.11
Textbook Question
Sketch a continuous function f on some interval that has the properties described. Answers will vary.
The function f satisfies f'(-2) = 2, f'(0) = 0, f'(1) = -3 and f'(4) = 1.

1
Understand that f'(x) represents the derivative of the function f(x), which gives the slope of the tangent line to the curve at any point x. The given values of f' indicate the slope of the tangent line at specific points.
At x = -2, f'(-2) = 2, which means the slope of the tangent line at this point is 2. This suggests that the function is increasing at x = -2.
At x = 0, f'(0) = 0, indicating that the tangent line is horizontal at this point. This could be a local maximum, minimum, or a point of inflection.
At x = 1, f'(1) = -3, meaning the slope of the tangent line is -3, so the function is decreasing at this point.
At x = 4, f'(4) = 1, which implies the slope of the tangent line is 1, indicating that the function is increasing at this point.
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