Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 4.7.57
Textbook Question
17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.
lim_x→π/2⁻ (π/2 - x) sec x
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1
Identify the limit to evaluate: lim_{x→π/2⁻} (π/2 - x) sec x. As x approaches π/2 from the left, sec x approaches infinity because cos x approaches 0.
Rewrite sec x in terms of cosine: sec x = 1/cos x. This gives us lim_{x→π/2⁻} (π/2 - x) / cos x.
Determine the form of the limit: As x approaches π/2, (π/2 - x) approaches 0 and cos x approaches 0, resulting in the indeterminate form 0/0.
Apply l'Hôpital's Rule, which states that if you have an indeterminate form, you can take the derivative of the numerator and the derivative of the denominator.
Differentiate the numerator (d/dx(π/2 - x) = -1) and the denominator (d/dx(cos x) = -sin x), then re-evaluate the limit: lim_{x→π/2⁻} (-1)/(-sin x).
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