Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
0. Functions
Combining Functions
2:10 minutes
Problem 1.44
Textbook Question
Textbook QuestionWorking with composite functions
Find possible choices for outer and inner functions ƒ and g such that the given function h equals ƒ o g.
h(x) = (2) / ( x⁶ + x² + 1)²
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Composite Functions
A composite function is formed when one function is applied to the result of another function. It is denoted as (ƒ o g)(x) = ƒ(g(x)), where g is the inner function and ƒ is the outer function. Understanding how to decompose a function into its components is essential for solving problems involving composite functions.
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Function Decomposition
Function decomposition involves breaking down a complex function into simpler parts, typically identifying an inner function and an outer function. This process is crucial for analyzing and manipulating functions, especially when working with compositions. In the context of the given function h(x), finding suitable ƒ and g requires recognizing how to express h in terms of simpler functions.
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Properties of Functions
Identifying Function Forms
Identifying function forms involves recognizing the structure of a function to determine potential inner and outer functions. For the function h(x) = (2) / (x⁶ + x² + 1)², one might consider the denominator as a candidate for the inner function g, while the outer function ƒ could be a transformation applied to the result of g. This skill is vital for effectively working with composite functions.
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