In this problem, we're asked to state the intervals for which the function \( f(x) \) is equal to \( \sqrt{2x - 1} \) is continuous. Now we're given a graph here so that we can clearly see visually where this function is continuous. Remember that when stating intervals, we're going to be using our interval notation of square brackets or parentheses based on what's happening with our function. Here, we can see that our function starts right here at \( x = 0.5 \) and continues on to infinity with no breaks, no asymptotes, it just continues on. So our function is actually continuous starting from 0.5 using a square bracket because this is a solid point all the way to infinity.
And of course, for infinity, we use just a parenthesis. So this is the only interval of our function; it's actually its domain because it's continuous over its entire domain. Let me know if you have any questions here. Thanks for watching.