Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Related Rates
Problem 3.11.16
Textbook Question
The edges of a cube increase at a rate of 2 cm/s. How fast is the volume changing when the length of each edge is 50 cm?
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1
Identify the formula for the volume of a cube, which is given by V = s^3, where s is the length of an edge.
Differentiate the volume formula with respect to time t to find the rate of change of volume, dV/dt = 3s^2 * ds/dt, where ds/dt is the rate of change of the edge length.
Substitute the given rate of change of the edge length, ds/dt = 2 cm/s, into the differentiated volume formula.
Substitute the length of the edge, s = 50 cm, into the equation to calculate dV/dt.
Calculate the final expression to find the rate at which the volume is changing at the moment when the edge length is 50 cm.
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