Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
5. Graphical Applications of Derivatives
Finding Global Extrema
Problem 4.1.49
Textbook Question
Absolute maxima and minima Determine the location and value of the absolute extreme values of ƒ on the given interval, if they exist.
ƒ(x) cos² x on [0,π]

1
First, understand that absolute extrema refer to the highest and lowest values a function can take on a given interval. For the function ƒ(x) = cos²(x) on the interval [0, π], we need to find these values.
To find the critical points where extrema might occur, take the derivative of ƒ(x) with respect to x. The derivative of cos²(x) can be found using the chain rule: ƒ'(x) = 2cos(x)(-sin(x)) = -2cos(x)sin(x).
Set the derivative ƒ'(x) = -2cos(x)sin(x) equal to zero to find critical points. This simplifies to 0 = -2cos(x)sin(x), which can be factored as 0 = -sin(2x). Solve for x to find the critical points within the interval [0, π].
Evaluate the function ƒ(x) = cos²(x) at the critical points found in the previous step, as well as at the endpoints of the interval, x = 0 and x = π. This will help determine the absolute maximum and minimum values.
Compare the values of ƒ(x) at the critical points and the endpoints to identify the absolute maximum and minimum values on the interval [0, π]. The largest value is the absolute maximum, and the smallest value is the absolute minimum.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Absolute Extrema
Absolute extrema refer to the highest and lowest values of a function over a specified interval. To find these values, one must evaluate the function at critical points, where the derivative is zero or undefined, as well as at the endpoints of the interval. The largest of these values is the absolute maximum, while the smallest is the absolute minimum.
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Critical Points
Critical points are values of the independent variable where the derivative of the function is either zero or does not exist. These points are essential in determining the behavior of the function, as they can indicate potential locations for local maxima, minima, or points of inflection. In the context of finding absolute extrema, critical points must be evaluated alongside the endpoints of the interval.
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Evaluating Functions on an Interval
Evaluating functions on a closed interval involves calculating the function's values at both endpoints and at any critical points found within the interval. This process is crucial for identifying absolute extrema, as it ensures that all potential maximum and minimum values are considered. For the function ƒ(x) = cos²(x) on the interval [0, π], this means checking the values at x = 0, x = π, and any critical points in between.
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