Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Related Rates
Problem 107b
Textbook Question
Suppose the cost of producing x lawn mowers is C(x) = −0.02x²+400x+5000.
b. Interpret the meaning of your results in part (a).
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1
Identify the cost function C(x) = -0.02x² + 400x + 5000, which is a quadratic function representing the cost of producing x lawn mowers.
Determine the vertex of the quadratic function, as it will provide insight into the minimum or maximum cost. Use the formula x = -b/(2a) where a = -0.02 and b = 400.
Calculate the x-coordinate of the vertex to find the number of lawn mowers that minimizes the cost.
Substitute the x-coordinate back into the cost function C(x) to find the minimum cost associated with producing that number of lawn mowers.
Interpret the results by discussing the significance of the minimum cost and the production level in terms of efficiency and profitability.
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