Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
5. Graphical Applications of Derivatives
Applied Optimization
Problem 4.R.35
Textbook Question
Optimal popcorn box A small popcorn box is created from a 12" x 12" sheet of paperboard by first cutting out four shaded rectangles, each of length x and width x/2 (see figure). The remaining paperboard is folded along the solid lines to form a box. What dimensions of the box maximize the volume of the box? <IMAGE>
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1
Define the dimensions of the box after cutting out the corners: the length will be (12 - x) inches, the width will be (12 - x) inches, and the height will be x/2 inches.
Write the volume V of the box as a function of x: V(x) = (12 - x)(12 - x)(x/2).
Simplify the volume function: V(x) = (12 - x)^2 * (x/2) = (1/2)(12 - x)^2 * x.
Find the critical points by taking the derivative of V with respect to x and setting it equal to zero: V'(x) = 0.
Determine the maximum volume by analyzing the critical points and endpoints of the interval for x, which is from 0 to 12.
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