Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Motion Analysis
Problem 6.R.11a
Textbook Question
{Use of Tech} Decreasing velocity A projectile is fired upward, and its velocity in m/s is given by v(t) = 200e^−t/10, for t≥0.
a. Graph the velocity function, for t≥0.

1
Identify the velocity function given in the problem: \( v(t) = 200e^{-t/10} \). This is an exponential decay function, where the velocity decreases over time.
Understand the behavior of the function: As \( t \) increases, the term \( e^{-t/10} \) decreases because the exponent is negative, leading to a decrease in \( v(t) \).
Determine the initial condition: At \( t = 0 \), the velocity \( v(0) = 200e^{0} = 200 \) m/s. This is the initial velocity of the projectile.
Consider the long-term behavior: As \( t \to \infty \), \( e^{-t/10} \to 0 \), so \( v(t) \to 0 \). This means the velocity approaches zero as time goes on.
To graph the function, plot \( v(t) \) against \( t \) for \( t \geq 0 \). Start at the point (0, 200) and show the curve decreasing towards zero, illustrating the exponential decay of velocity over time.
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