Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
3. Techniques of Differentiation
The Chain Rule
Problem 3.7.103b
Textbook Question
{Use of Tech} Hours of daylight The number of hours of daylight at any point on Earth fluctuates throughout the year. In the Northern Hemisphere, the shortest day is on the winter solstice and the longest day is on the summer solstice. At 40° north latitude, the length of a day is approximated by D(t) = 12−3 cos (2π(t+10) / 365), where D is measured in hours and 0≤t≤365 is measured in days, with t=0 corresponding to January 1.
b. Find the rate at which the daylight function changes.

1
Step 1: Identify the function D(t) = 12 - 3 \cos\left(\frac{2\pi(t+10)}{365}\right) that represents the length of daylight in hours as a function of time t in days.
Step 2: To find the rate at which the daylight function changes, we need to compute the derivative of D(t) with respect to t, denoted as D'(t).
Step 3: Apply the chain rule to differentiate the cosine function. The derivative of \cos(u) with respect to u is -\sin(u), and the derivative of u = \frac{2\pi(t+10)}{365} with respect to t is \frac{2\pi}{365}.
Step 4: Combine the results from Step 3 to find D'(t). The derivative is D'(t) = 3 \cdot \sin\left(\frac{2\pi(t+10)}{365}\right) \cdot \frac{2\pi}{365}.
Step 5: Simplify the expression for D'(t) to get the final form of the derivative, which represents the rate of change of daylight hours with respect to time.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Differentiation
Differentiation is a fundamental concept in calculus that involves finding the derivative of a function. The derivative represents the rate of change of a function with respect to its variable. In this context, differentiating the daylight function D(t) will provide the rate at which the number of daylight hours changes over time, which is essential for solving the problem.
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Cosine Function
The cosine function is a periodic function that describes the relationship between the angle and the lengths of the sides of a right triangle. In the given daylight function D(t), the cosine term models the seasonal variation in daylight hours, reflecting how daylight changes throughout the year. Understanding its properties, such as periodicity and amplitude, is crucial for interpreting the function's behavior.
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Rate of Change
The rate of change refers to how a quantity changes in relation to another variable. In this scenario, it specifically pertains to how the number of daylight hours changes with respect to time (days of the year). By calculating the derivative of D(t), we can determine the instantaneous rate of change of daylight hours at any given day, which is key to answering the question.
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