Hey, everyone. We just learned that for many functions, our limit will actually just be the same as our function value. So let's keep this in mind as we work through these examples. Now this first example asks us to find the limit of 7 as x approaches 2. Now seeing this might be a bit confusing because how can I find the limit of 7 as x approaches 2?
There's nowhere to plug that value into this function. But because this is a constant function, I don't have to do any plugging in here because my function value the whole time is 7. As x approaches 2, as x approaches 5, as x approaches 1,000,000, it's always going to be 7. So here, the limit of 7 as x approaches 2 is just 7. Now let's look at our next example.
Here, we're asked to find the limit of 2xx2+3x as x approaches negative 1. So here we just want to plug negative 1 into our polynomial in order to get this limit. So I'm gonna take 2 times negative one-squared plus 3 times negative one, and this is going to be my answer here. Now actually doing this algebra, 2 times negative one squared is going to give me 2 and then 3 times negative one is negative 3. So here I have 2 minus 3 which will give me negative one for the limit of this function as x approaches negative one.
Now let's look at our final example here and here we have a root, the limit of the square root of 3x squared minus 2 as x approaches 3. So with this basic root we want to go ahead and plug in our x value of 3. So doing that here I get the square root of 3 times 3 squared minus 2. Now 3 times 3 squared minus 2 will end up giving me 25 so this is just the square root of 25 or fully simplified, taking that square root, 5, as the limit of this function as x approaches 3. Feel free to let me know if you have any questions here, I'll see you in the next video.