Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 3.4.11a
Textbook Question
7–14. Find the derivative the following ways:
a. Using the Product Rule (Exercises 7–10) or the Quotient Rule (Exercises 11–14). Simplify your result.
f(w) = w³ -w / w
![](/channels/images/assetPage/verifiedSolution.png)
1
Identify the function f(w) = \frac{w^3 - w}{w} and simplify it by dividing each term in the numerator by the denominator.
Simplify the expression: \frac{w^3}{w} - \frac{w}{w} = w^2 - 1.
Recognize that the simplified function f(w) = w^2 - 1 is a polynomial function.
Differentiate the simplified function using the power rule: \frac{d}{dw}(w^2) = 2w and \frac{d}{dw}(-1) = 0.
Combine the derivatives to find the derivative of the function: f'(w) = 2w.
Recommended similar problem, with video answer:
![](/channels/images/assetPage/verifiedSolution.png)
This video solution was recommended by our tutors as helpful for the problem above
Video duration:
4mPlay a video:
Was this helpful?
Related Videos
Related Practice