Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
6. Derivatives of Inverse, Exponential, & Logarithmic Functions
Derivatives of Inverse Trigonometric Functions
Problem 3.10.13
Textbook Question
Evaluate the derivative of the following functions.
f(x) = sin-1 2x

1
Step 1: Recognize that \( f(x) = \sin^{-1}(2x) \) is the inverse sine function, also known as arcsine, applied to \( 2x \).
Step 2: Recall the derivative formula for the inverse sine function: \( \frac{d}{dx}[\sin^{-1}(u)] = \frac{1}{\sqrt{1-u^2}} \cdot \frac{du}{dx} \), where \( u \) is a function of \( x \).
Step 3: Identify \( u = 2x \) in this problem, so you need to find \( \frac{du}{dx} \).
Step 4: Differentiate \( u = 2x \) with respect to \( x \), which gives \( \frac{du}{dx} = 2 \).
Step 5: Substitute \( u = 2x \) and \( \frac{du}{dx} = 2 \) into the derivative formula: \( \frac{d}{dx}[\sin^{-1}(2x)] = \frac{1}{\sqrt{1-(2x)^2}} \cdot 2 \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivative
The derivative of a function measures how the function's output value changes as its input value changes. It is defined as the limit of the average rate of change of the function over an interval as the interval approaches zero. In calculus, the derivative is often denoted as f'(x) or df/dx, and it provides critical information about the function's behavior, such as its slope and points of tangency.
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Inverse Trigonometric Functions
Inverse trigonometric functions, such as sin<sup>-1</sup>(x), are the functions that reverse the action of the standard trigonometric functions. For example, sin<sup>-1</sup>(x) gives the angle whose sine is x. These functions have specific domains and ranges, and their derivatives can be derived using implicit differentiation or known derivative formulas, which are essential for evaluating derivatives involving these functions.
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Chain Rule
The chain rule is a fundamental technique in calculus used to differentiate composite functions. It states that if a function y = f(g(x)) is composed of two functions, the derivative can be found by multiplying the derivative of the outer function f with the derivative of the inner function g. This rule is particularly useful when dealing with functions like sin<sup>-1</sup>(2x), where the inner function (2x) must be differentiated alongside the outer function (sin<sup>-1</sup>), requiring careful application of the chain rule.
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