Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
The Chain Rule
Problem 47
Textbook Question
Calculate the derivative of the following functions.
y = (1 + 2 tan u)4.5
![](/channels/images/assetPage/verifiedSolution.png)
1
Step 1: Identify the function y = (1 + 2 \tan u)^{4.5} as a composite function, which requires the use of the chain rule to differentiate.
Step 2: Apply the chain rule. The chain rule states that if you have a composite function y = f(g(u)), then the derivative y' is f'(g(u)) * g'(u).
Step 3: Differentiate the outer function f(v) = v^{4.5} with respect to v, which gives f'(v) = 4.5v^{3.5}.
Step 4: Differentiate the inner function g(u) = 1 + 2 \tan u with respect to u, which gives g'(u) = 2 \sec^2 u.
Step 5: Combine the results from Steps 3 and 4 using the chain rule: y' = 4.5(1 + 2 \tan u)^{3.5} \cdot 2 \sec^2 u.
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