Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 2.R.83
Textbook Question
b. Estimate a solution to the equation in the given interval using a root finder.
x=cos x; (0,π/2)
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1
Identify the function to analyze: f(x) = x - cos(x). This is derived from rearranging the equation x = cos(x).
Determine the interval of interest, which is (0, π/2). Evaluate f(x) at the endpoints of the interval: f(0) and f(π/2).
Calculate f(0) = 0 - cos(0) = -1 and f(π/2) = π/2 - cos(π/2) = π/2. Note that f(0) is negative and f(π/2) is positive.
Since f(0) < 0 and f(π/2) > 0, by the Intermediate Value Theorem, there is at least one root in the interval (0, π/2).
Use a numerical method such as the bisection method or Newton's method to iteratively find a more precise estimate of the root within the interval.
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