Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
6. Derivatives of Inverse, Exponential, & Logarithmic Functions
Derivatives of Inverse Trigonometric Functions
Problem 3.10.51
Textbook Question
47–56. Derivatives of inverse functions at a point Consider the following functions. In each case, without finding the inverse, evaluate the derivative of the inverse at the given point.
f(x)=tan x; (1,π/4)
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1
Identify the function f(x) = tan(x) and the point (1, π/4) where we need to evaluate the derivative of the inverse function.
Recall the relationship between the derivatives of a function and its inverse: if y = f(x), then the derivative of the inverse function at a point is given by the formula (f^(-1))'(y) = 1 / f'(x) where y = f(x).
Calculate the derivative of f(x) = tan(x). The derivative is f'(x) = sec^2(x).
Evaluate f'(x) at the point x = π/4. Since f(π/4) = 1, we need to find sec^2(π/4).
Use the value of f'(π/4) to find the derivative of the inverse function at the point y = 1 using the formula from step 2.
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