Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Implicit Differentiation
Problem 3.8.62a
Textbook Question
60–62. {Use of Tech} Multiple tangent lines Complete the following steps. <IMAGE>
a. Find equations of all lines tangent to the curve at the given value of x.
4x³ =y²(4−x); x=2 (cissoid of Diocles)

1
First, differentiate the given equation of the curve, which is 4x³ = y²(4 - x), with respect to x to find the slope of the tangent line at any point on the curve.
Next, substitute x = 2 into the original equation to find the corresponding y-coordinate(s) on the curve.
After finding the y-coordinate(s), use the derivative obtained in step 1 to evaluate the slope of the tangent line at the point(s) (2, y).
With the slope and the point(s) (2, y) determined, apply the point-slope form of the equation of a line, which is y - y₁ = m(x - x₁), to find the equation(s) of the tangent line(s).
Finally, simplify the equation(s) of the tangent line(s) to express them in slope-intercept form or standard form as required.
Was this helpful?
Watch next
Master Finding The Implicit Derivative with a bite sized video explanation from Nick
Start learningRelated Videos
Related Practice