Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 66e
Textbook Question
Population growth Consider the following population functions.
e.Use a graphing utility to graph the population and its growth rate.
p(t) = 600 (t²+3/t²+9)
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1
Step 1: Identify the function for the population, which is given as \( p(t) = 600 \left( \frac{t^2 + 3}{t^2 + 9} \right) \). This function represents the population at time \( t \).
Step 2: To find the growth rate of the population, we need to compute the derivative of \( p(t) \) with respect to \( t \). This involves using the quotient rule for derivatives, which is \( \frac{d}{dt} \left( \frac{u}{v} \right) = \frac{u'v - uv'}{v^2} \), where \( u = t^2 + 3 \) and \( v = t^2 + 9 \).
Step 3: Calculate the derivatives \( u' \) and \( v' \). For \( u = t^2 + 3 \), \( u' = 2t \). For \( v = t^2 + 9 \), \( v' = 2t \).
Step 4: Substitute \( u, v, u', \) and \( v' \) into the quotient rule formula to find \( p'(t) \), the growth rate of the population. This gives \( p'(t) = 600 \left( \frac{(2t)(t^2 + 9) - (t^2 + 3)(2t)}{(t^2 + 9)^2} \right) \).
Step 5: Simplify the expression for \( p'(t) \) to obtain a more manageable form for graphing. This involves expanding and combining like terms in the numerator, and then simplifying the entire expression.
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