Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 3.4.21
Textbook Question
Derivatives Find and simplify the derivative of the following functions.
f(x) = x /x+1
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1
Step 1: Recognize that the function \( f(x) = \frac{x}{x+1} \) is a quotient of two functions, \( u(x) = x \) and \( v(x) = x+1 \). To find the derivative, we will use the Quotient Rule.
Step 2: Recall the Quotient Rule, which states that if \( f(x) = \frac{u(x)}{v(x)} \), then \( f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2} \).
Step 3: Differentiate \( u(x) = x \) to get \( u'(x) = 1 \), and differentiate \( v(x) = x+1 \) to get \( v'(x) = 1 \).
Step 4: Substitute \( u(x) \), \( u'(x) \), \( v(x) \), and \( v'(x) \) into the Quotient Rule formula: \( f'(x) = \frac{1 \cdot (x+1) - x \cdot 1}{(x+1)^2} \).
Step 5: Simplify the expression obtained in Step 4 to find the simplified form of the derivative.
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