{Use of Tech} Bungee jumper A woman attached to a bungee cor...

Question

{Use of Tech} Bungee jumper A woman attached to a bungee cord jumps from a bridge that is 30 m above a river. Her height in meters above the river t seconds after the jump is y(t) = 15(1+e^−t cos t), for t ≥ 0.
b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s.

b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s.

Accepted Answer

A drone is flying vertically with its height above the ground in meters given by the function F of T equals 30. 2 minus E raise this -0.2 T cosine 2T, where T is the time in seconds after takeoff for T greater than equal to 0. Using a graphing utility, determine the intervals during the 1st 8 seconds when the drone is moving downwards and upwards. I've provided the graph of this function here. And all of our important points on the crap. So let's first find the intervals. Where the drone is flying upward. So we can follow these on our graph. We start at 030 on the graph, and go up to 1.52 82.02. So, this first section here goes upwards. We then go down until 3.09 seconds, and then start going up again. At 4.66 seconds is where it stops. We go down again, and then up once more, starting at 6.23 seconds and stopping. At 7.8 seconds. So our upward intervals are as follows. From 0 to 1.52. 3.09 to 4.66. And finally, 6.23 to 7.80. We can also find our downwards intervals. Starting at 1.52, we go down until 3.09. And then we rise up until 4.66, going down until 6.23. Finally, Right after 7.8, we go back down and end at 8. So, for downwards, we have the intervals, 1.52. To 3.09. 4.66. 6.23. And 7.80. To 8. These are the intervals where we're going both upwards and downwards. This is our answer. OK, I hope to help you solve the problem. Thank you for watching. Goodbye.

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