Consider the function $e^t$. As $t$ approaches infinity, $e^t$ grows exponentially without bound. Therefore, $\lim_{t \to \infty} e^t = \infty$.
Now, consider the function $e^t$ as $t$ approaches negative infinity. As $t$ becomes more negative, $e^t$ approaches zero because the exponential function decays rapidly. Therefore, $\lim_{t \to -\infty} e^t = 0$.
Next, consider the function $e^{-t}$ as $t$ approaches infinity. Notice that $e^{-t} = \frac{1}{e^t}$. As $t$ becomes very large, $e^t$ becomes very large, making $\frac{1}{e^t}$ approach zero. Therefore, $\lim_{t \to \infty} e^{-t} = 0$.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Limits at Infinity
Limits at infinity refer to the behavior of a function as the input approaches positive or negative infinity. Understanding these limits helps determine the end behavior of functions, which is crucial in calculus for analyzing asymptotic behavior and graphing functions.
Exponential functions, such as e^t, are functions of the form f(t) = a^t, where 'a' is a positive constant. The base 'e' (approximately 2.718) is particularly important in calculus due to its unique properties, including its derivative being equal to the function itself, which simplifies many calculations involving growth and decay.
The function e^t grows rapidly as t approaches infinity, leading to a limit of infinity. Conversely, e^−t approaches zero as t approaches infinity, indicating decay. Understanding these behaviors is essential for evaluating the specified limits and interpreting their implications in various contexts.