- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Introduction to Trigonometric Functions
Problem 70
Textbook Question
Observers at positions A and B 2 km apart simultaneously measure the angle of elevation of a weather balloon to be 40° and 70°, respectively. If the balloon is directly above a point on the line segment between A and B, find the height of the balloon.

1
First, visualize the problem by drawing a diagram. Place points A and B on a horizontal line, 2 km apart. Let point C be the point directly below the balloon on the line segment AB. The balloon is at point D, directly above C. You have two right triangles: ACD and BCD.
In triangle ACD, angle A is 40°, and AC is the horizontal distance from A to C. In triangle BCD, angle B is 70°, and BC is the horizontal distance from B to C. The height of the balloon is the length of CD, which is the same in both triangles.
Use the tangent function, which relates the angle of elevation to the opposite side (height of the balloon) and the adjacent side (horizontal distance). For triangle ACD, use the equation: \( \tan(40°) = \frac{CD}{AC} \). Solve for CD: \( CD = AC \cdot \tan(40°) \).
Similarly, for triangle BCD, use the equation: \( \tan(70°) = \frac{CD}{BC} \). Solve for CD: \( CD = BC \cdot \tan(70°) \).
Since AC + BC = 2 km (the total distance between A and B), you now have two equations for CD in terms of AC and BC. Set the two expressions for CD equal to each other and solve for AC and BC. Substitute back to find the height CD, which is the height of the balloon.
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