Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
6. Derivatives of Inverse, Exponential, & Logarithmic Functions
Derivatives of Exponential & Logarithmic Functions
Problem 3.9.9
Textbook Question
Find d/dx(ln√x²+1).

1
Rewrite the expression using properties of logarithms: ln(√(x² + 1)) can be expressed as (1/2)ln(x² + 1).
Differentiate the expression (1/2)ln(x² + 1) using the chain rule, which states that d/dx[ln(u)] = (1/u)(du/dx).
Identify u as (x² + 1) and find its derivative du/dx, which is 2x.
Substitute u and du/dx back into the derivative formula: d/dx[(1/2)ln(u)] = (1/2)(1/(x² + 1))(2x).
Simplify the expression to get the final derivative in terms of x.
Recommended similar problem, with video answer:

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
7mPlay a video:
Was this helpful?
Watch next
Master Derivatives of General Exponential Functions with a bite sized video explanation from Callie
Start learningRelated Videos
Related Practice