Use the graph of ƒ to find ƒ⁻¹ (2),ƒ⁻¹ (9), and ƒ⁻¹ (12) <IMAGE>
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Exponential & Logarithmic Equations
Problem 13Briggs - 3rd Edition
Textbook Question
The parabola y=x²+1 consists of two one-to-one functions, g₁(x) and g₂(x). Complete each exercise and confirm that your answers are consistent with the graphs displayed in the figure. <IMAGE>
Find formulas for g₁((x) and g₁⁻¹(x). State the domain and range of each function.

1
<strong>Step 1:</strong> Identify the one-to-one functions from the parabola . Since a parabola is symmetric about its vertex, we can split it into two functions: one for the left side and one for the right side. For the right side, where , the function is .
<strong>Step 2:</strong> Determine the inverse of . To find , start by setting and solve for . Rearrange to get , then take the square root: . Thus, .
<strong>Step 3:</strong> State the domain and range of . Since and we are considering , the domain of is . The range is because the smallest value of is 1 when .
<strong>Step 4:</strong> State the domain and range of . The domain of is because the expression under the square root, , must be non-negative. The range is because the square root function outputs non-negative values.
<strong>Step 5:</strong> Verify consistency with the graph. Check that the domain and range of and match the sections of the parabola and its inverse on the graph. Ensure that covers the right side of the parabola and reflects this section across the line .
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
One-to-One Functions
A one-to-one function is a function where each output is produced by exactly one input. This means that if f(a) = f(b), then a must equal b. For the parabola y = x² + 1, it is not one-to-one over its entire domain, but can be restricted to intervals where it is, allowing for the definition of inverse functions.
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Inverse Functions
An inverse function essentially reverses the effect of the original function. If g(x) is a function, then its inverse g⁻¹(x) satisfies the condition g(g⁻¹(x)) = x for all x in the domain of g⁻¹. To find the inverse of a one-to-one function, you typically swap the x and y variables and solve for y.
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Domain and Range
The domain of a function is the set of all possible input values (x-values) that the function can accept, while the range is the set of all possible output values (y-values) that the function can produce. For the functions g₁(x) and g₂(x) derived from the parabola, understanding their domains and ranges is crucial for accurately defining their behavior and ensuring the validity of their inverses.
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