Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Motion Analysis
Problem 3.6.11a
Textbook Question
Highway travel A state patrol station is located on a straight north-south freeway. A patrol car leaves the station at 9:00 A.M. heading north with position function s = f(t) that gives its location in miles t hours after 9:00 A.M. (see figure). Assume s is positive when the car is north of the patrol station. <IMAGE>
a. Determine the average velocity of the car during the first 45 minutes of the trip.
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1
Convert the time of 45 minutes into hours, which is 0.75 hours.
Identify the position function s = f(t) that describes the car's location in miles at time t hours after 9:00 A.M.
Calculate the position of the car at t = 0 (which is 9:00 A.M.) and at t = 0.75 (which is 9:45 A.M.) using the position function.
Use the formula for average velocity, which is given by the change in position divided by the change in time: average velocity = (f(0.75) - f(0)) / (0.75 - 0).
Substitute the values obtained from the position function into the average velocity formula to find the average velocity during the first 45 minutes.
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