Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
1. Limits and Continuity
Introduction to Limits
Problem 2.7.19
Textbook Question
Use the precise definition of a limit to prove the following limits. Specify a relationship between ε and δ that guarantees the limit exists.
lim x→1 (8x+5)=13
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1
Step 1: Recall the precise definition of a limit. The limit of a function f(x) as x approaches a value c is L if for every ε > 0, there exists a δ > 0 such that if 0 < |x - c| < δ, then |f(x) - L| < ε.
Step 2: Identify the function f(x) and the values of c and L from the given limit. Here, f(x) = 8x + 5, c = 1, and L = 13.
Step 3: Set up the inequality |f(x) - L| < ε using the function and limit value. This becomes |(8x + 5) - 13| < ε, which simplifies to |8x - 8| < ε.
Step 4: Simplify the inequality |8x - 8| < ε to find a relationship between x and ε. This simplifies to 8|x - 1| < ε, which further simplifies to |x - 1| < ε/8.
Step 5: Establish the relationship between ε and δ. From the inequality |x - 1| < ε/8, we can choose δ = ε/8. Therefore, for every ε > 0, if 0 < |x - 1| < δ, then |f(x) - 13| < ε, proving the limit.
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