Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
0. Functions
Exponential Functions
Problem 3.9.97b
Textbook Question
97–100. Logistic growth Scientists often use the logistic growth function P(t) = P₀K / P₀+(K−P₀)e^−r₀t to model population growth, where P₀ is the initial population at time t=0, K is the carrying capacity, and r₀ is the base growth rate. The carrying capacity is a theoretical upper bound on the total population that the surrounding environment can support. The figure shows the sigmoid (S-shaped) curve associated with a typical logistic model. <IMAGE>
{Use of Tech} Gone fishing When a reservoir is created by a new dam, 50 fish are introduced into the reservoir, which has an estimated carrying capacity of 8000 fish. A logistic model of the fish population is P(t) = 400,000 / 50+7950e^−0.5t, where t is measured in years.
b. How long does it take for the population to reach 5000 fish? How long does it take for the population to reach 90% of the carrying capacity?

1
Identify the logistic growth function given in the problem: P(t) = \frac{400,000}{50 + 7950e^{-0.5t}}.
To find the time it takes for the population to reach 5000 fish, set P(t) = 5000 and solve for t: \frac{400,000}{50 + 7950e^{-0.5t}} = 5000.
Rearrange the equation to isolate the exponential term: 50 + 7950e^{-0.5t} = \frac{400,000}{5000}.
Calculate \frac{400,000}{5000} to simplify the equation: 50 + 7950e^{-0.5t} = 80.
Subtract 50 from both sides and solve for e^{-0.5t}: 7950e^{-0.5t} = 30. Then, divide both sides by 7950 and take the natural logarithm to solve for t.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Logistic Growth Model
The logistic growth model describes how a population grows in a limited environment, characterized by an initial exponential growth phase followed by a slowdown as the population approaches a maximum capacity, known as the carrying capacity (K). The model is represented by the equation P(t) = P₀K / (P₀ + (K - P₀)e^(-r₀t)), where P₀ is the initial population, r₀ is the growth rate, and t is time. This S-shaped curve illustrates how populations stabilize as resources become scarce.
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Carrying Capacity
Carrying capacity (K) refers to the maximum population size that an environment can sustain indefinitely without degrading the habitat. In the context of the logistic growth model, it acts as a threshold that limits population growth as resources become limited. Understanding carrying capacity is crucial for predicting population dynamics and managing ecological systems, as it helps determine when a population will stabilize.
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Exponential Growth and Decay
Exponential growth occurs when the growth rate of a population is proportional to its current size, leading to rapid increases when resources are abundant. Conversely, exponential decay describes a decrease in population size when resources are limited or when mortality rates exceed birth rates. In logistic growth, the initial phase often resembles exponential growth until the effects of limited resources begin to slow the growth, transitioning the population towards the carrying capacity.
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