Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
4. Applications of Derivatives
Differentials
Problem 4.7.28
Textbook Question
17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.
lim_x→ 0⁺ (x - 3 √x) / (x - √x)
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1
First, substitute x = 0 into the limit expression to check if it results in an indeterminate form. You will find that both the numerator and denominator approach 0, indicating that l'Hôpital's Rule may be applicable.
Next, apply l'Hôpital's Rule, which states that if the limit results in an indeterminate form of type 0/0, you can take the derivative of the numerator and the derivative of the denominator separately.
Differentiate the numerator, which is (x - 3√x). The derivative will involve using the power rule and the chain rule for the square root term.
Differentiate the denominator, which is (x - √x). Again, apply the power rule and the chain rule to find the derivative of the square root term.
Finally, substitute x = 0 into the new limit expression formed by the derivatives of the numerator and denominator to evaluate the limit.
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