Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
2. Intro to Derivatives
Tangent Lines and Derivatives
Problem 39a
Textbook Question
Find the derivative function f' for the following functions f.
f(x) = 2/3x+1; a= -1
![](/channels/images/assetPage/verifiedSolution.png)
1
Step 1: Identify the function f(x) = \frac{2}{3}x + 1. This is a linear function of the form f(x) = ax + b, where a = \frac{2}{3} and b = 1.
Step 2: Recall that the derivative of a linear function f(x) = ax + b is simply the coefficient of x, which is a. In this case, the derivative f'(x) will be \frac{2}{3}.
Step 3: Since the derivative of a constant is zero, the +1 in the function does not affect the derivative. Therefore, f'(x) = \frac{2}{3}.
Step 4: Evaluate the derivative at the given point a = -1. Since the derivative is constant, f'(-1) = \frac{2}{3}.
Step 5: Conclude that the derivative function f'(x) is constant and equal to \frac{2}{3} for all x, including at x = -1.
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