Table of contents
- 1. Introduction to Biology2h 42m
- 2. Chemistry3h 40m
- 3. Water1h 26m
- 4. Biomolecules2h 23m
- 5. Cell Components2h 26m
- 6. The Membrane2h 31m
- 7. Energy and Metabolism2h 0m
- 8. Respiration2h 40m
- 9. Photosynthesis2h 49m
- 10. Cell Signaling59m
- 11. Cell Division2h 47m
- 12. Meiosis2h 0m
- 13. Mendelian Genetics4h 44m
- Introduction to Mendel's Experiments7m
- Genotype vs. Phenotype17m
- Punnett Squares13m
- Mendel's Experiments26m
- Mendel's Laws18m
- Monohybrid Crosses19m
- Test Crosses14m
- Dihybrid Crosses20m
- Punnett Square Probability26m
- Incomplete Dominance vs. Codominance20m
- Epistasis7m
- Non-Mendelian Genetics12m
- Pedigrees6m
- Autosomal Inheritance21m
- Sex-Linked Inheritance43m
- X-Inactivation9m
- 14. DNA Synthesis2h 27m
- 15. Gene Expression3h 20m
- 16. Regulation of Expression3h 31m
- Introduction to Regulation of Gene Expression13m
- Prokaryotic Gene Regulation via Operons27m
- The Lac Operon21m
- Glucose's Impact on Lac Operon25m
- The Trp Operon20m
- Review of the Lac Operon & Trp Operon11m
- Introduction to Eukaryotic Gene Regulation9m
- Eukaryotic Chromatin Modifications16m
- Eukaryotic Transcriptional Control22m
- Eukaryotic Post-Transcriptional Regulation28m
- Eukaryotic Post-Translational Regulation13m
- 17. Viruses37m
- 18. Biotechnology2h 58m
- 19. Genomics17m
- 20. Development1h 5m
- 21. Evolution3h 1m
- 22. Evolution of Populations3h 52m
- 23. Speciation1h 37m
- 24. History of Life on Earth2h 6m
- 25. Phylogeny2h 31m
- 26. Prokaryotes4h 59m
- 27. Protists1h 12m
- 28. Plants1h 22m
- 29. Fungi36m
- 30. Overview of Animals34m
- 31. Invertebrates1h 2m
- 32. Vertebrates50m
- 33. Plant Anatomy1h 3m
- 34. Vascular Plant Transport1h 2m
- 35. Soil37m
- 36. Plant Reproduction47m
- 37. Plant Sensation and Response1h 9m
- 38. Animal Form and Function1h 19m
- 39. Digestive System1h 10m
- 40. Circulatory System1h 57m
- 41. Immune System1h 12m
- 42. Osmoregulation and Excretion50m
- 43. Endocrine System1h 4m
- 44. Animal Reproduction1h 2m
- 45. Nervous System1h 55m
- 46. Sensory Systems46m
- 47. Muscle Systems23m
- 48. Ecology3h 11m
- Introduction to Ecology20m
- Biogeography14m
- Earth's Climate Patterns50m
- Introduction to Terrestrial Biomes10m
- Terrestrial Biomes: Near Equator13m
- Terrestrial Biomes: Temperate Regions10m
- Terrestrial Biomes: Northern Regions15m
- Introduction to Aquatic Biomes27m
- Freshwater Aquatic Biomes14m
- Marine Aquatic Biomes13m
- 49. Animal Behavior28m
- 50. Population Ecology3h 41m
- Introduction to Population Ecology28m
- Population Sampling Methods23m
- Life History12m
- Population Demography17m
- Factors Limiting Population Growth14m
- Introduction to Population Growth Models22m
- Linear Population Growth6m
- Exponential Population Growth29m
- Logistic Population Growth32m
- r/K Selection10m
- The Human Population22m
- 51. Community Ecology2h 46m
- Introduction to Community Ecology2m
- Introduction to Community Interactions9m
- Community Interactions: Competition (-/-)38m
- Community Interactions: Exploitation (+/-)23m
- Community Interactions: Mutualism (+/+) & Commensalism (+/0)9m
- Community Structure35m
- Community Dynamics26m
- Geographic Impact on Communities21m
- 52. Ecosystems2h 36m
- 53. Conservation Biology24m
14. DNA Synthesis
Chargaff's Rules
Problem 3`
Textbook Question
In analyzing the number of different bases in a DNA sample, which result would be consistent with the base-pairing rules?
a. A=G
b. A+G=C+T
c. A+T=G+C
d. A=C

1
Understand the base-pairing rules in DNA: Adenine (A) pairs with Thymine (T), and Guanine (G) pairs with Cytosine (C). This means the amount of A should equal the amount of T, and the amount of G should equal the amount of C.
Consider the option A=G. This would imply that the amount of Adenine is equal to the amount of Guanine, which contradicts the base-pairing rules since A pairs with T, not G.
Evaluate the option A+G=C+T. This option suggests that the sum of Adenine and Guanine equals the sum of Cytosine and Thymine. This is consistent with the base-pairing rules because A pairs with T and G pairs with C, so the total number of purines (A and G) should equal the total number of pyrimidines (C and T).
Analyze the option A+T=G+C. This implies that the sum of Adenine and Thymine equals the sum of Guanine and Cytosine. While this might seem consistent at first glance, it does not necessarily follow the base-pairing rules directly, as it does not account for the specific pairing of A with T and G with C.
Consider the option A=C. This suggests that the amount of Adenine is equal to the amount of Cytosine, which contradicts the base-pairing rules since A pairs with T, not C.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Base Pairing Rules
Base pairing rules in DNA refer to the specific pairing between nitrogenous bases: adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C). This complementary base pairing is due to hydrogen bonding, where A forms two hydrogen bonds with T, and G forms three hydrogen bonds with C, ensuring the DNA double helix structure is stable and consistent.
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Chargaff's Rules
Chargaff's Rule
Chargaff's Rule states that in a DNA molecule, the amount of adenine (A) is equal to thymine (T), and the amount of guanine (G) is equal to cytosine (C). This rule is derived from the base pairing rules and implies that the total purines (A+G) equal the total pyrimidines (C+T), maintaining a consistent ratio across different organisms.
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Chargaff's Rules
DNA Structure
DNA is structured as a double helix, composed of two strands running in opposite directions. Each strand is made up of a sugar-phosphate backbone and nitrogenous bases. The specific pairing of bases (A with T and G with C) across the two strands allows for the replication and transmission of genetic information, as each strand can serve as a template for creating a new complementary strand.
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Discovering the Structure of DNA