Table of contents
- 1. Introduction to Biology2h 40m
- 2. Chemistry3h 40m
- 3. Water1h 26m
- 4. Biomolecules2h 23m
- 5. Cell Components2h 26m
- 6. The Membrane2h 31m
- 7. Energy and Metabolism2h 0m
- 8. Respiration2h 40m
- 9. Photosynthesis2h 49m
- 10. Cell Signaling59m
- 11. Cell Division2h 47m
- 12. Meiosis2h 0m
- 13. Mendelian Genetics4h 41m
- Introduction to Mendel's Experiments7m
- Genotype vs. Phenotype17m
- Punnett Squares13m
- Mendel's Experiments26m
- Mendel's Laws18m
- Monohybrid Crosses16m
- Test Crosses14m
- Dihybrid Crosses20m
- Punnett Square Probability26m
- Incomplete Dominance vs. Codominance20m
- Epistasis7m
- Non-Mendelian Genetics12m
- Pedigrees6m
- Autosomal Inheritance21m
- Sex-Linked Inheritance43m
- X-Inactivation9m
- 14. DNA Synthesis2h 27m
- 15. Gene Expression3h 20m
- 16. Regulation of Expression3h 31m
- Introduction to Regulation of Gene Expression13m
- Prokaryotic Gene Regulation via Operons27m
- The Lac Operon21m
- Glucose's Impact on Lac Operon25m
- The Trp Operon20m
- Review of the Lac Operon & Trp Operon11m
- Introduction to Eukaryotic Gene Regulation9m
- Eukaryotic Chromatin Modifications16m
- Eukaryotic Transcriptional Control22m
- Eukaryotic Post-Transcriptional Regulation28m
- Eukaryotic Post-Translational Regulation13m
- 17. Viruses37m
- 18. Biotechnology2h 58m
- 19. Genomics17m
- 20. Development1h 5m
- 21. Evolution3h 1m
- 22. Evolution of Populations3h 52m
- 23. Speciation1h 37m
- 24. History of Life on Earth2h 6m
- 25. Phylogeny2h 31m
- 26. Prokaryotes4h 59m
- 27. Protists1h 12m
- 28. Plants1h 22m
- 29. Fungi36m
- 30. Overview of Animals34m
- 31. Invertebrates1h 2m
- 32. Vertebrates50m
- 33. Plant Anatomy1h 3m
- 34. Vascular Plant Transport2m
- 35. Soil37m
- 36. Plant Reproduction47m
- 37. Plant Sensation and Response1h 9m
- 38. Animal Form and Function1h 19m
- 39. Digestive System10m
- 40. Circulatory System1h 57m
- 41. Immune System1h 12m
- 42. Osmoregulation and Excretion50m
- 43. Endocrine System4m
- 44. Animal Reproduction2m
- 45. Nervous System55m
- 46. Sensory Systems46m
- 47. Muscle Systems23m
- 48. Ecology3h 11m
- Introduction to Ecology20m
- Biogeography14m
- Earth's Climate Patterns50m
- Introduction to Terrestrial Biomes10m
- Terrestrial Biomes: Near Equator13m
- Terrestrial Biomes: Temperate Regions10m
- Terrestrial Biomes: Northern Regions15m
- Introduction to Aquatic Biomes27m
- Freshwater Aquatic Biomes14m
- Marine Aquatic Biomes13m
- 49. Animal Behavior28m
- 50. Population Ecology3h 41m
- Introduction to Population Ecology28m
- Population Sampling Methods23m
- Life History12m
- Population Demography17m
- Factors Limiting Population Growth14m
- Introduction to Population Growth Models22m
- Linear Population Growth6m
- Exponential Population Growth29m
- Logistic Population Growth32m
- r/K Selection10m
- The Human Population22m
- 51. Community Ecology2h 46m
- Introduction to Community Ecology2m
- Introduction to Community Interactions9m
- Community Interactions: Competition (-/-)38m
- Community Interactions: Exploitation (+/-)23m
- Community Interactions: Mutualism (+/+) & Commensalism (+/0)9m
- Community Structure35m
- Community Dynamics26m
- Geographic Impact on Communities21m
- 52. Ecosystems2h 36m
- 53. Conservation Biology24m
8. Respiration
Review of Aerobic Cellular Respiration
5:06 minutes
Problem 10
Textbook Question
Textbook QuestionEarly estimates suggested that the oxidation of glucose via aerobic respiration would produce 38 ATP. Based on what you know of the theoretical yields of ATP from cellular respiration, show how this total was determined. Why do biologists now think this amount of ATP per molecule of glucose is not achieved in cells?
Verified step by step guidance
1
Step 1: Understand the stages of cellular respiration. Cellular respiration consists of glycolysis, the Krebs cycle, and oxidative phosphorylation (including the electron transport chain). Each stage contributes to ATP production.
Step 2: Calculate ATP from glycolysis. Glycolysis converts one glucose molecule into two pyruvate molecules, producing a net gain of 2 ATP and 2 NADH. The 2 NADH can potentially produce 6 ATP via oxidative phosphorylation (assuming 3 ATP per NADH).
Step 3: Calculate ATP from the Krebs cycle. Each acetyl-CoA entering the Krebs cycle generates 1 ATP (or GTP), 3 NADH, and 1 FADH2. Since two acetyl-CoA molecules are produced from one glucose, this results in 2 ATP, 6 NADH, and 2 FADH2. The 6 NADH can produce 18 ATP and the 2 FADH2 can produce 4 ATP via oxidative phosphorylation.
Step 4: Sum the ATP totals. Adding the ATP from glycolysis (2 ATP + 6 ATP from NADH), the Krebs cycle (2 ATP + 18 ATP from NADH + 4 ATP from FADH2), and the ATP directly produced from oxidative phosphorylation of the NADH and FADH2 generated in these processes, the theoretical maximum yield would be 38 ATP (2+6+2+18+4+6 from oxidative phosphorylation of the NADH from glycolysis).
Step 5: Understand why actual ATP yield is lower. Biologists now recognize that the theoretical maximum is seldom reached due to losses like the cost of transporting pyruvate into mitochondria, and the use of the proton gradient for purposes other than ATP synthesis (like heat production and transport of other ions). Additionally, the ratio of ATP per NADH and FADH2 can vary depending on the cell type and conditions, often being lower than the theoretical 3 and 2, respectively.
Recommended similar problem, with video answer:
Verified Solution
Video duration:
5mPlay a video:
Related Videos
Related Practice