A 39.0 g piece of aluminum metal has a volume of 14.4 cm 3 . Calculate the apparent weight of the piece of metal when it is immersed in chloroform. Density of chloroform at 25 °C is 1.49 g/cm 3 .

Here in this practice question it says, a 39 gram piece of aluminum metal has a volume of 14.4 centimeters cubed. Calculate the apparent weight of the piece of metal when it is immersed in chloroform. Here we're told the density of chloroform at 25 degrees Celsius is 1.49 grams per centimeters cubed. Alright. To answer this question, we're gonna use the formula that our buoyant force f equals here our density, which is p, times our volume of the water that's displaced, times our gravitational field strength, which is g. Here we have to solve for f. Now our g, our gravitational, field strength is equal to 9.8 Newtons over kilograms. And because we have kilograms here, we're going to have to convert these grams in our density also to kilograms. So here we do 1.49 grams per centimeters cubed. Remember, it is 1 kilogram is 10 to the 3 grams. So the density here is 0.00149 kilograms per centimeters cubed. That's what we put here for p. Next, we have our, volume, which is centimeters cubed, which we can keep because these centimeters cubed will cancel out with these centimeters cubed, followed by our n or 9.8 newtons over kilograms. Kilograms would cancel out here. What we get left at the end is 0.210 Newtons. This would be our final answer, which is option b. Here, the 39 grams piece of aluminum metal wasn't necessary in terms of this formula, so we could ignore it. Again, our final answer would be option b.